71490843653 has 2 divisors, whose sum is σ = 71490843654. Its totient is φ = 71490843652.

The previous prime is 71490843617. The next prime is 71490843659. The reversal of 71490843653 is 35634809417.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70025332129 + 1465511524 = 264623^2 + 38282^2 .

It is an emirp because it is prime and its reverse (35634809417) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 71490843653 - 2¹⁰ = 71490842629 is a prime.

It is a super-3 number, since 3×71490843653³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (71490843659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35745421826 + 35745421827.

It is an arithmetic number, because the mean of its divisors is an integer number (35745421827).

Almost surely, 2^71490843653 is an apocalyptic number.

It is an amenable number.

71490843653 is a deficient number, since it is larger than the sum of its proper divisors (1).

71490843653 is an equidigital number, since it uses as much as digits as its factorization.

71490843653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 50.

The spelling of 71490843653 in words is "seventy-one billion, four hundred ninety million, eight hundred forty-three thousand, six hundred fifty-three".