Base | Representation |
---|---|
bin | 110101011010001001110… |
… | …1111111010011100011001 |
3 | 221222201221012212221222102 |
4 | 1222310103233322130121 |
5 | 1430231200142423441 |
6 | 23340051443133145 |
7 | 1355220465141266 |
oct | 152642357723431 |
9 | 27881835787872 |
10 | 7340430436121 |
11 | 2380071686712 |
12 | 9a675b3741b5 |
13 | 413279746703 |
14 | 1b53c8b9026d |
15 | cae1c56b69b |
hex | 6ad13bfa719 |
7340430436121 has 2 divisors, whose sum is σ = 7340430436122. Its totient is φ = 7340430436120.
The previous prime is 7340430436091. The next prime is 7340430436127. The reversal of 7340430436121 is 1216340340437.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7334152250896 + 6278185225 = 2708164^2 + 79235^2 .
It is a cyclic number.
It is not a de Polignac number, because 7340430436121 - 214 = 7340430419737 is a prime.
It is not a weakly prime, because it can be changed into another prime (7340430436127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3670215218060 + 3670215218061.
It is an arithmetic number, because the mean of its divisors is an integer number (3670215218061).
Almost surely, 27340430436121 is an apocalyptic number.
It is an amenable number.
7340430436121 is a deficient number, since it is larger than the sum of its proper divisors (1).
7340430436121 is an equidigital number, since it uses as much as digits as its factorization.
7340430436121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 7340430436121 its reverse (1216340340437), we get a palindrome (8556770776558).
The spelling of 7340430436121 in words is "seven trillion, three hundred forty billion, four hundred thirty million, four hundred thirty-six thousand, one hundred twenty-one".
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