73419810053 has 2 divisors, whose sum is σ = 73419810054. Its totient is φ = 73419810052.

The previous prime is 73419810029. The next prime is 73419810059. The reversal of 73419810053 is 35001891437.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51709850404 + 21709959649 = 227398^2 + 147343^2 .

It is an emirp because it is prime and its reverse (35001891437) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 73419810053 - 2¹⁴ = 73419793669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (73419810059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36709905026 + 36709905027.

It is an arithmetic number, because the mean of its divisors is an integer number (36709905027).

Almost surely, 2^73419810053 is an apocalyptic number.

It is an amenable number.

73419810053 is a deficient number, since it is larger than the sum of its proper divisors (1).

73419810053 is an equidigital number, since it uses as much as digits as its factorization.

73419810053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 41.

The spelling of 73419810053 in words is "seventy-three billion, four hundred nineteen million, eight hundred ten thousand, fifty-three".