Base | Representation |
---|---|
bin | 1000110001000… |
… | …11000110110001 |
3 | 12010101102120001 |
4 | 10120203012301 |
5 | 122311402423 |
6 | 11144150001 |
7 | 1552054216 |
oct | 430430661 |
9 | 163342501 |
10 | 73544113 |
11 | 38571865 |
12 | 20768301 |
13 | 1230ca36 |
14 | 9aa5b0d |
15 | 66cacad |
hex | 46231b1 |
73544113 has 2 divisors, whose sum is σ = 73544114. Its totient is φ = 73544112.
The previous prime is 73544111. The next prime is 73544131. The reversal of 73544113 is 31144537.
Together with next prime (73544131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 45792289 + 27751824 = 6767^2 + 5268^2 .
It is an emirp because it is prime and its reverse (31144537) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 73544113 - 21 = 73544111 is a prime.
Together with 73544111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (73544111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36772056 + 36772057.
It is an arithmetic number, because the mean of its divisors is an integer number (36772057).
Almost surely, 273544113 is an apocalyptic number.
It is an amenable number.
73544113 is a deficient number, since it is larger than the sum of its proper divisors (1).
73544113 is an equidigital number, since it uses as much as digits as its factorization.
73544113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5040, while the sum is 28.
The square root of 73544113 is about 8575.7864362401. The cubic root of 73544113 is about 418.9697215358.
The spelling of 73544113 in words is "seventy-three million, five hundred forty-four thousand, one hundred thirteen".
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