Base | Representation |
---|---|
bin | 100010011010011010… |
… | …1010111010100110001 |
3 | 21001202021111001221111 |
4 | 1010310311113110301 |
5 | 2202322104122213 |
6 | 53541035353321 |
7 | 5224221563416 |
oct | 1046465272461 |
9 | 231667431844 |
10 | 73900848433 |
11 | 29383114255 |
12 | 123a52b2841 |
13 | 6c796617a9 |
14 | 3810b1a10d |
15 | 1dc7ceca3d |
hex | 1134d57531 |
73900848433 has 2 divisors, whose sum is σ = 73900848434. Its totient is φ = 73900848432.
The previous prime is 73900848431. The next prime is 73900848457. The reversal of 73900848433 is 33484800937.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60480089329 + 13420759104 = 245927^2 + 115848^2 .
It is a cyclic number.
It is not a de Polignac number, because 73900848433 - 21 = 73900848431 is a prime.
It is a super-2 number, since 2×739008484332 (a number of 23 digits) contains 22 as substring.
Together with 73900848431, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (73900848431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36950424216 + 36950424217.
It is an arithmetic number, because the mean of its divisors is an integer number (36950424217).
Almost surely, 273900848433 is an apocalyptic number.
It is an amenable number.
73900848433 is a deficient number, since it is larger than the sum of its proper divisors (1).
73900848433 is an equidigital number, since it uses as much as digits as its factorization.
73900848433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 49.
The spelling of 73900848433 in words is "seventy-three billion, nine hundred million, eight hundred forty-eight thousand, four hundred thirty-three".
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