Base | Representation |
---|---|
bin | 10101100010011000000… |
… | …10100111111101111011 |
3 | 2121202002120121122210121 |
4 | 22301030002213331323 |
5 | 44111020043200243 |
6 | 1323542253154111 |
7 | 104315066221501 |
oct | 12611402477573 |
9 | 2552076548717 |
10 | 740010131323 |
11 | 265922477531 |
12 | bb503a8b937 |
13 | 54a23658a68 |
14 | 27b60d8c671 |
15 | 143b18e11ed |
hex | ac4c0a7f7b |
740010131323 has 2 divisors, whose sum is σ = 740010131324. Its totient is φ = 740010131322.
The previous prime is 740010131299. The next prime is 740010131363. The reversal of 740010131323 is 323131010047.
It is a weak prime.
It is an emirp because it is prime and its reverse (323131010047) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-740010131323 is a prime.
It is a super-2 number, since 2×7400101313232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (740010131363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 370005065661 + 370005065662.
It is an arithmetic number, because the mean of its divisors is an integer number (370005065662).
Almost surely, 2740010131323 is an apocalyptic number.
740010131323 is a deficient number, since it is larger than the sum of its proper divisors (1).
740010131323 is an equidigital number, since it uses as much as digits as its factorization.
740010131323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 740010131323 in words is "seven hundred forty billion, ten million, one hundred thirty-one thousand, three hundred twenty-three".
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