Base | Representation |
---|---|
bin | 1000110100101… |
… | …01001011000011 |
3 | 12011021011110102 |
4 | 10122111023003 |
5 | 122421330311 |
6 | 11202153015 |
7 | 1556041322 |
oct | 432251303 |
9 | 164234412 |
10 | 74011331 |
11 | 38860899 |
12 | 2095276b |
13 | 124445b4 |
14 | 9b880b9 |
15 | 676e43b |
hex | 46952c3 |
74011331 has 2 divisors, whose sum is σ = 74011332. Its totient is φ = 74011330.
The previous prime is 74011313. The next prime is 74011337. The reversal of 74011331 is 13311047.
It is a happy number.
Together with previous prime (74011313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (13311047) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-74011331 is a prime.
It is a super-3 number, since 3×740113313 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (74011337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37005665 + 37005666.
It is an arithmetic number, because the mean of its divisors is an integer number (37005666).
Almost surely, 274011331 is an apocalyptic number.
74011331 is a deficient number, since it is larger than the sum of its proper divisors (1).
74011331 is an equidigital number, since it uses as much as digits as its factorization.
74011331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
The square root of 74011331 is about 8602.9838428303. The cubic root of 74011331 is about 419.8550728234.
Adding to 74011331 its reverse (13311047), we get a palindrome (87322378).
The spelling of 74011331 in words is "seventy-four million, eleven thousand, three hundred thirty-one".
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