Base | Representation |
---|---|
bin | 100010011111010110… |
… | …1111010101001100101 |
3 | 21002011211111120210212 |
4 | 1010332231322221211 |
5 | 2203142031340013 |
6 | 54005321425205 |
7 | 5231304201653 |
oct | 1047655725145 |
9 | 232154446725 |
10 | 74066668133 |
11 | 29458781027 |
12 | 1243093b205 |
13 | 6ca4b0c163 |
14 | 3828b61dd3 |
15 | 1dd76546a8 |
hex | 113eb7aa65 |
74066668133 has 2 divisors, whose sum is σ = 74066668134. Its totient is φ = 74066668132.
The previous prime is 74066668121. The next prime is 74066668157. The reversal of 74066668133 is 33186666047.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67258272964 + 6808395169 = 259342^2 + 82513^2 .
It is an emirp because it is prime and its reverse (33186666047) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 74066668133 - 210 = 74066667109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (74066668033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37033334066 + 37033334067.
It is an arithmetic number, because the mean of its divisors is an integer number (37033334067).
Almost surely, 274066668133 is an apocalyptic number.
It is an amenable number.
74066668133 is a deficient number, since it is larger than the sum of its proper divisors (1).
74066668133 is an equidigital number, since it uses as much as digits as its factorization.
74066668133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2612736, while the sum is 50.
The spelling of 74066668133 in words is "seventy-four billion, sixty-six million, six hundred sixty-eight thousand, one hundred thirty-three".
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