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74320942576117 is a prime number
BaseRepresentation
bin10000111001100000110001…
…011000011011000111110101
3100202011000100021101121002011
4100321200301120123013311
534220133242244413432
6422022323014444221
721440340145361656
oct2071406130330765
9322130307347064
1074320942576117
11217543755a5436
128403a91363671
13326158638b5c3
14144d21d46d52d
1588d3d1a17847
hex43983161b1f5

74320942576117 has 2 divisors, whose sum is σ = 74320942576118. Its totient is φ = 74320942576116.

The previous prime is 74320942576091. The next prime is 74320942576169. The reversal of 74320942576117 is 71167524902347.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54404992448676 + 19915950127441 = 7375974^2 + 4462729^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-74320942576117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (74320942576417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37160471288058 + 37160471288059.

It is an arithmetic number, because the mean of its divisors is an integer number (37160471288059).

Almost surely, 274320942576117 is an apocalyptic number.

It is an amenable number.

74320942576117 is a deficient number, since it is larger than the sum of its proper divisors (1).

74320942576117 is an equidigital number, since it uses as much as digits as its factorization.

74320942576117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17781120, while the sum is 58.

The spelling of 74320942576117 in words is "seventy-four trillion, three hundred twenty billion, nine hundred forty-two million, five hundred seventy-six thousand, one hundred seventeen".