Base | Representation |
---|---|
bin | 100010100111111011… |
… | …0011011011000011111 |
3 | 21002220212101020201011 |
4 | 1011033312123120133 |
5 | 2204234123041111 |
6 | 54054030400051 |
7 | 5241364344553 |
oct | 1051766333037 |
9 | 232825336634 |
10 | 74354112031 |
11 | 29595a59971 |
12 | 124b1060027 |
13 | 701c531ac4 |
14 | 3854dc7863 |
15 | 1e029d3021 |
hex | 114fd9b61f |
74354112031 has 2 divisors, whose sum is σ = 74354112032. Its totient is φ = 74354112030.
The previous prime is 74354111987. The next prime is 74354112047. The reversal of 74354112031 is 13021145347.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 74354112031 - 27 = 74354111903 is a prime.
It is a super-2 number, since 2×743541120312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 74354111984 and 74354112002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (74354112331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37177056015 + 37177056016.
It is an arithmetic number, because the mean of its divisors is an integer number (37177056016).
Almost surely, 274354112031 is an apocalyptic number.
74354112031 is a deficient number, since it is larger than the sum of its proper divisors (1).
74354112031 is an equidigital number, since it uses as much as digits as its factorization.
74354112031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 74354112031 its reverse (13021145347), we get a palindrome (87375257378).
The spelling of 74354112031 in words is "seventy-four billion, three hundred fifty-four million, one hundred twelve thousand, thirty-one".
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