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74356980433 is a prime number
BaseRepresentation
bin100010101000000000…
…1010111101011010001
321002221001202222102021
41011100001113223101
52204240341333213
654054212051441
75241430622341
oct1052001275321
9232831688367
1074356980433
1129597638a4a
12124b2003b81
13701ccc7598
143855532d21
151e02d9cd8d
hex1150057ad1

74356980433 has 2 divisors, whose sum is σ = 74356980434. Its totient is φ = 74356980432.

The previous prime is 74356980431. The next prime is 74356980517. The reversal of 74356980433 is 33408965347.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59717674384 + 14639306049 = 244372^2 + 120993^2 .

It is a cyclic number.

It is not a de Polignac number, because 74356980433 - 21 = 74356980431 is a prime.

It is a super-3 number, since 3×743569804333 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 74356980431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (74356980431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37178490216 + 37178490217.

It is an arithmetic number, because the mean of its divisors is an integer number (37178490217).

Almost surely, 274356980433 is an apocalyptic number.

It is an amenable number.

74356980433 is a deficient number, since it is larger than the sum of its proper divisors (1).

74356980433 is an equidigital number, since it uses as much as digits as its factorization.

74356980433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 52.

The spelling of 74356980433 in words is "seventy-four billion, three hundred fifty-six million, nine hundred eighty thousand, four hundred thirty-three".