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745808095117 is a prime number
BaseRepresentation
bin10101101101001011010…
…00000110011110001101
32122022001122111201220101
422312211220012132031
544204403333020432
61330341451451101
7104611551132151
oct12664550063615
92568048451811
10745808095117
11268328254548
12100661756a91
1355438906777
1428151009061
151460091b4e7
hexada5a0678d

745808095117 has 2 divisors, whose sum is σ = 745808095118. Its totient is φ = 745808095116.

The previous prime is 745808095111. The next prime is 745808095127. The reversal of 745808095117 is 711590808547.

745808095117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 453917502756 + 291890592361 = 673734^2 + 540269^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-745808095117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (745808095111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 372904047558 + 372904047559.

It is an arithmetic number, because the mean of its divisors is an integer number (372904047559).

Almost surely, 2745808095117 is an apocalyptic number.

It is an amenable number.

745808095117 is a deficient number, since it is larger than the sum of its proper divisors (1).

745808095117 is an equidigital number, since it uses as much as digits as its factorization.

745808095117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2822400, while the sum is 55.

The spelling of 745808095117 in words is "seven hundred forty-five billion, eight hundred eight million, ninety-five thousand, one hundred seventeen".