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7490113 is a prime number
BaseRepresentation
bin11100100100101001000001
3112002112111121
4130210221001
53404140423
6424312241
7120444031
oct34445101
915075447
107490113
114256484
122612681
131723327
14dcd8c1
159ce45d
hex724a41

7490113 has 2 divisors, whose sum is σ = 7490114. Its totient is φ = 7490112.

The previous prime is 7490101. The next prime is 7490141. The reversal of 7490113 is 3110947.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5702544 + 1787569 = 2388^2 + 1337^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-7490113 is a prime.

It is a super-2 number, since 2×74901132 = 112203585505538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (7490143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3745056 + 3745057.

It is an arithmetic number, because the mean of its divisors is an integer number (3745057).

Almost surely, 27490113 is an apocalyptic number.

It is an amenable number.

7490113 is a deficient number, since it is larger than the sum of its proper divisors (1).

7490113 is an equidigital number, since it uses as much as digits as its factorization.

7490113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

The square root of 7490113 is about 2736.8070812536. The cubic root of 7490113 is about 195.6573302423.

The spelling of 7490113 in words is "seven million, four hundred ninety thousand, one hundred thirteen".