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749081955253 is a prime number
BaseRepresentation
bin10101110011010001100…
…00111000101110110101
32122121111210212001201111
422321220300320232311
544233104440032003
61332042401555021
7105055643363662
oct12715060705665
92577453761644
10749081955253
11269758265085
12101216045a71
135583ac65b08
1428381b3ca69
1514743058e6d
hexae68c38bb5

749081955253 has 2 divisors, whose sum is σ = 749081955254. Its totient is φ = 749081955252.

The previous prime is 749081955229. The next prime is 749081955263. The reversal of 749081955253 is 352559180947.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 645141484849 + 103940470404 = 803207^2 + 322398^2 .

It is a cyclic number.

It is not a de Polignac number, because 749081955253 - 221 = 749079858101 is a prime.

It is a super-2 number, since 2×7490819552532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (749081955263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 374540977626 + 374540977627.

It is an arithmetic number, because the mean of its divisors is an integer number (374540977627).

Almost surely, 2749081955253 is an apocalyptic number.

It is an amenable number.

749081955253 is a deficient number, since it is larger than the sum of its proper divisors (1).

749081955253 is an equidigital number, since it uses as much as digits as its factorization.

749081955253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608000, while the sum is 58.

The spelling of 749081955253 in words is "seven hundred forty-nine billion, eighty-one million, nine hundred fifty-five thousand, two hundred fifty-three".