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75641131 is a prime number
BaseRepresentation
bin1001000001000…
…11000100101011
312021022222010101
410200203010223
5123331004011
611301130231
71605640036
oct440430453
9167288111
1075641131
1139774335
12213b9977
1312895387
14a09001d
1569922c1
hex482312b

75641131 has 2 divisors, whose sum is σ = 75641132. Its totient is φ = 75641130.

The previous prime is 75641129. The next prime is 75641141. The reversal of 75641131 is 13114657.

It is a weak prime.

It is an emirp because it is prime and its reverse (13114657) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 75641131 - 21 = 75641129 is a prime.

It is a super-2 number, since 2×756411312 = 11443161397918322, which contains 22 as substring.

Together with 75641129, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 75641131.

It is not a weakly prime, because it can be changed into another prime (75641101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37820565 + 37820566.

It is an arithmetic number, because the mean of its divisors is an integer number (37820566).

Almost surely, 275641131 is an apocalyptic number.

75641131 is a deficient number, since it is larger than the sum of its proper divisors (1).

75641131 is an equidigital number, since it uses as much as digits as its factorization.

75641131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2520, while the sum is 28.

The square root of 75641131 is about 8697.1909833003. The cubic root of 75641131 is about 422.9145932076.

Adding to 75641131 its reverse (13114657), we get a palindrome (88755788).

The spelling of 75641131 in words is "seventy-five million, six hundred forty-one thousand, one hundred thirty-one".