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75900642048131 is a prime number
BaseRepresentation
bin10001010000011111111110…
…110011101011100010000011
3100221202000211020122101220112
4101100133332303223202003
534422024003331020011
6425232135032501535
721662432444343155
oct2120377663534203
9327660736571815
1075900642048131
112220331078a76a
12861a07754a8ab
1333475275857b4
1414a58799a4ad5
158b953acba58b
hex4507feceb883

75900642048131 has 2 divisors, whose sum is σ = 75900642048132. Its totient is φ = 75900642048130.

The previous prime is 75900642047947. The next prime is 75900642048157. The reversal of 75900642048131 is 13184024600957.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 75900642048131 - 242 = 71502595537027 is a prime.

It is a super-2 number, since 2×759006420481312 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 75900642048131.

It is not a weakly prime, because it can be changed into another prime (75900642048431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37950321024065 + 37950321024066.

It is an arithmetic number, because the mean of its divisors is an integer number (37950321024066).

It is a 1-persistent number, because it is pandigital, but 2⋅75900642048131 = 151801284096262 is not.

Almost surely, 275900642048131 is an apocalyptic number.

75900642048131 is a deficient number, since it is larger than the sum of its proper divisors (1).

75900642048131 is an equidigital number, since it uses as much as digits as its factorization.

75900642048131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 75900642048131 in words is "seventy-five trillion, nine hundred billion, six hundred forty-two million, forty-eight thousand, one hundred thirty-one".