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7672402011343 is a prime number
BaseRepresentation
bin110111110100101111011…
…0010111110010011001111
31000011110210212222021212011
41233221132302332103033
52001201034403330333
624152353002122051
71421212163026336
oct157513662762317
930143725867764
107672402011343
112498935a09653
12a3ab67ab0327
13438673241764
141c74bc116d1d
15d489b99e9cd
hex6fa5ecbe4cf

7672402011343 has 2 divisors, whose sum is σ = 7672402011344. Its totient is φ = 7672402011342.

The previous prime is 7672402011331. The next prime is 7672402011359. The reversal of 7672402011343 is 3431102042767.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-7672402011343 is a prime.

It is a super-2 number, since 2×76724020113432 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 7672402011296 and 7672402011305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7672402012343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3836201005671 + 3836201005672.

It is an arithmetic number, because the mean of its divisors is an integer number (3836201005672).

Almost surely, 27672402011343 is an apocalyptic number.

7672402011343 is a deficient number, since it is larger than the sum of its proper divisors (1).

7672402011343 is an equidigital number, since it uses as much as digits as its factorization.

7672402011343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 169344, while the sum is 40.

The spelling of 7672402011343 in words is "seven trillion, six hundred seventy-two billion, four hundred two million, eleven thousand, three hundred forty-three".