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769840351213 is a prime number
BaseRepresentation
bin10110011001111100000…
…11111000011111101101
32201121002111102211122111
423030332003320133231
5100103113112214323
61345354302244021
7106422235005553
oct13147603703755
92647074384574
10769840351213
1127753a89921a
12105249b86611
13577987b794b
1429390a3dbd3
151505a67ec0d
hexb33e0f87ed

769840351213 has 2 divisors, whose sum is σ = 769840351214. Its totient is φ = 769840351212.

The previous prime is 769840351193. The next prime is 769840351307. The reversal of 769840351213 is 312153048967.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 666668984004 + 103171367209 = 816498^2 + 321203^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-769840351213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (769840351913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 384920175606 + 384920175607.

It is an arithmetic number, because the mean of its divisors is an integer number (384920175607).

It is a 2-persistent number, because it is pandigital, and so is 2⋅769840351213 = 1539680702426, but 3⋅769840351213 = 2309521053639 is not.

Almost surely, 2769840351213 is an apocalyptic number.

It is an amenable number.

769840351213 is a deficient number, since it is larger than the sum of its proper divisors (1).

769840351213 is an equidigital number, since it uses as much as digits as its factorization.

769840351213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 49.

The spelling of 769840351213 in words is "seven hundred sixty-nine billion, eight hundred forty million, three hundred fifty-one thousand, two hundred thirteen".