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77375231135513 is a prime number
BaseRepresentation
bin10001100101111101010011…
…001010101000111100011001
3101010221222222220011102200022
4101211331103022220330121
540120203433132314023
6432321405050320225
722204114233645323
oct2145752312507431
9333858886142608
1077375231135513
1122721718898323
128817a08429075
1334235b72a321c
141516da4482613
158e2a923757c8
hex465f532a8f19

77375231135513 has 2 divisors, whose sum is σ = 77375231135514. Its totient is φ = 77375231135512.

The previous prime is 77375231135491. The next prime is 77375231135537. The reversal of 77375231135513 is 31553113257377.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77099147094544 + 276084040969 = 8780612^2 + 525437^2 .

It is an emirp because it is prime and its reverse (31553113257377) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 77375231135513 - 216 = 77375231069977 is a prime.

It is a super-3 number, since 3×773752311355133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (77375231135593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38687615567756 + 38687615567757.

It is an arithmetic number, because the mean of its divisors is an integer number (38687615567757).

Almost surely, 277375231135513 is an apocalyptic number.

It is an amenable number.

77375231135513 is a deficient number, since it is larger than the sum of its proper divisors (1).

77375231135513 is an equidigital number, since it uses as much as digits as its factorization.

77375231135513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6945750, while the sum is 53.

The spelling of 77375231135513 in words is "seventy-seven trillion, three hundred seventy-five billion, two hundred thirty-one million, one hundred thirty-five thousand, five hundred thirteen".