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77800431225493 is a prime number
BaseRepresentation
bin10001101100001001010011…
…000100010000101010010101
3101012110122111211011000100001
4101230021103010100222111
540144140240343203433
6433245005200051301
722246616133041404
oct2154112304205225
9335418454130301
1077800431225493
1122875a831a0269
1288862b3003b31
13345471a733cc2
14152d7bd3d563b
158edb7b2b757d
hex46c253110a95

77800431225493 has 2 divisors, whose sum is σ = 77800431225494. Its totient is φ = 77800431225492.

The previous prime is 77800431225479. The next prime is 77800431225499. The reversal of 77800431225493 is 39452213400877.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52925304900484 + 24875126325009 = 7274978^2 + 4987497^2 .

It is an emirp because it is prime and its reverse (39452213400877) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-77800431225493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (77800431225499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38900215612746 + 38900215612747.

It is an arithmetic number, because the mean of its divisors is an integer number (38900215612747).

Almost surely, 277800431225493 is an apocalyptic number.

It is an amenable number.

77800431225493 is a deficient number, since it is larger than the sum of its proper divisors (1).

77800431225493 is an equidigital number, since it uses as much as digits as its factorization.

77800431225493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10160640, while the sum is 55.

The spelling of 77800431225493 in words is "seventy-seven trillion, eight hundred billion, four hundred thirty-one million, two hundred twenty-five thousand, four hundred ninety-three".