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78212145131 is a prime number
BaseRepresentation
bin100100011010111001…
…1101001111111101011
321110212201221122011222
41020311303221333223
52240134302121011
655532525412255
75436112156511
oct1106563517753
9243781848158
1078212145131
113019579827a
12131a910a08b
1374b5907b23
143add5444b1
15207b563ddb
hex1235ce9feb

78212145131 has 2 divisors, whose sum is σ = 78212145132. Its totient is φ = 78212145130.

The previous prime is 78212145049. The next prime is 78212145133. The reversal of 78212145131 is 13154121287.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 78212145131 - 214 = 78212128747 is a prime.

It is a super-2 number, since 2×782121451312 (a number of 23 digits) contains 22 as substring.

Together with 78212145133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 78212145091 and 78212145100.

It is not a weakly prime, because it can be changed into another prime (78212145133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39106072565 + 39106072566.

It is an arithmetic number, because the mean of its divisors is an integer number (39106072566).

Almost surely, 278212145131 is an apocalyptic number.

78212145131 is a deficient number, since it is larger than the sum of its proper divisors (1).

78212145131 is an equidigital number, since it uses as much as digits as its factorization.

78212145131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13440, while the sum is 35.

The spelling of 78212145131 in words is "seventy-eight billion, two hundred twelve million, one hundred forty-five thousand, one hundred thirty-one".