Search a number
-
+
7828294909 is a prime number
BaseRepresentation
bin1110100101001101…
…00100110011111101
3202012120022120210111
413102212210303331
5112013020414114
63332443310021
7364664260141
oct72246446375
922176276714
107828294909
113357960916
12162581b311
13979ab4986
1454396d221
1530c3cebc4
hex1d29a4cfd

7828294909 has 2 divisors, whose sum is σ = 7828294910. Its totient is φ = 7828294908.

The previous prime is 7828294891. The next prime is 7828294913. The reversal of 7828294909 is 9094928287.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7613086009 + 215208900 = 87253^2 + 14670^2 .

It is an emirp because it is prime and its reverse (9094928287) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7828294909 - 213 = 7828286717 is a prime.

It is a super-2 number, since 2×78282949092 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7828264909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3914147454 + 3914147455.

It is an arithmetic number, because the mean of its divisors is an integer number (3914147455).

Almost surely, 27828294909 is an apocalyptic number.

It is an amenable number.

7828294909 is a deficient number, since it is larger than the sum of its proper divisors (1).

7828294909 is an equidigital number, since it uses as much as digits as its factorization.

7828294909 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5225472, while the sum is 58.

The square root of 7828294909 is about 88477.6520314593. The cubic root of 7828294909 is about 1985.5876337397.

The spelling of 7828294909 in words is "seven billion, eight hundred twenty-eight million, two hundred ninety-four thousand, nine hundred nine".