Base | Representation |
---|---|
bin | 10001110101000111100001… |
… | …101100010111011100101011 |
3 | 101021122120222212101221100012 |
4 | 101311013201230113130223 |
5 | 40234241011113131201 |
6 | 434440135143402135 |
7 | 22342304320553333 |
oct | 2165074154273453 |
9 | 337576885357305 |
10 | 78417004427051 |
11 | 22a93512743454 |
12 | 89658a815334b |
13 | 349a8cbb1c644 |
14 | 15515907ba0c3 |
15 | 90ec161035bb |
hex | 4751e1b1772b |
78417004427051 has 2 divisors, whose sum is σ = 78417004427052. Its totient is φ = 78417004427050.
The previous prime is 78417004427017. The next prime is 78417004427053. The reversal of 78417004427051 is 15072440071487.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 78417004427051 - 26 = 78417004426987 is a prime.
It is a super-2 number, since 2×784170044270512 (a number of 29 digits) contains 22 as substring.
Together with 78417004427053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (78417004427053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39208502213525 + 39208502213526.
It is an arithmetic number, because the mean of its divisors is an integer number (39208502213526).
Almost surely, 278417004427051 is an apocalyptic number.
78417004427051 is a deficient number, since it is larger than the sum of its proper divisors (1).
78417004427051 is an equidigital number, since it uses as much as digits as its factorization.
78417004427051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1756160, while the sum is 50.
The spelling of 78417004427051 in words is "seventy-eight trillion, four hundred seventeen billion, four million, four hundred twenty-seven thousand, fifty-one".
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