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7913001233101 is a prime number
BaseRepresentation
bin111001100100110001110…
…1000001010101011001101
31001000110211122212010120111
41303021203220022223031
52014121311303424401
624455103234320021
71444460355462346
oct163114350125315
931013748763514
107913001233101
1125809809a4a88
12a79714129011
134552677c8773
141d4dc41c90cd
15dac7e322e51
hex73263a0aacd

7913001233101 has 2 divisors, whose sum is σ = 7913001233102. Its totient is φ = 7913001233100.

The previous prime is 7913001233087. The next prime is 7913001233119. The reversal of 7913001233101 is 1013321003197.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6357967293001 + 1555033940100 = 2521501^2 + 1247010^2 .

It is an emirp because it is prime and its reverse (1013321003197) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7913001233101 - 25 = 7913001233069 is a prime.

It is a super-3 number, since 3×79130012331013 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7913001293101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3956500616550 + 3956500616551.

It is an arithmetic number, because the mean of its divisors is an integer number (3956500616551).

Almost surely, 27913001233101 is an apocalyptic number.

It is an amenable number.

7913001233101 is a deficient number, since it is larger than the sum of its proper divisors (1).

7913001233101 is an equidigital number, since it uses as much as digits as its factorization.

7913001233101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402, while the sum is 31.

Adding to 7913001233101 its reverse (1013321003197), we get a palindrome (8926322236298).

The spelling of 7913001233101 in words is "seven trillion, nine hundred thirteen billion, one million, two hundred thirty-three thousand, one hundred one".