Base | Representation |
---|---|
bin | 100100110110101100… |
… | …1110100000000010011 |
3 | 21120021202002012202021 |
4 | 1021231121310000103 |
5 | 2244042043110413 |
6 | 100205245432311 |
7 | 5501166334414 |
oct | 1115531640023 |
9 | 246252065667 |
10 | 79144894483 |
11 | 30624258706 |
12 | 1340956b697 |
13 | 7603c29a15 |
14 | 3b8b38780b |
15 | 20d33ae18d |
hex | 126d674013 |
79144894483 has 2 divisors, whose sum is σ = 79144894484. Its totient is φ = 79144894482.
The previous prime is 79144894481. The next prime is 79144894513. The reversal of 79144894483 is 38449844197.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 79144894483 - 21 = 79144894481 is a prime.
Together with 79144894481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (79144894481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39572447241 + 39572447242.
It is an arithmetic number, because the mean of its divisors is an integer number (39572447242).
Almost surely, 279144894483 is an apocalyptic number.
79144894483 is a deficient number, since it is larger than the sum of its proper divisors (1).
79144894483 is an equidigital number, since it uses as much as digits as its factorization.
79144894483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27869184, while the sum is 61.
The spelling of 79144894483 in words is "seventy-nine billion, one hundred forty-four million, eight hundred ninety-four thousand, four hundred eighty-three".
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