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7923002121113 is a prime number
BaseRepresentation
bin111001101001011011110…
…1110100001101110011001
31001001102122122021212211012
41303102313232201232121
52014302302020333423
624503435452143305
71445263243563302
oct163226756415631
931042578255735
107923002121113
112585143166192
12a7b645467b35
1345619c737191
141d56924dd7a9
15db167309078
hex734b7ba1b99

7923002121113 has 2 divisors, whose sum is σ = 7923002121114. Its totient is φ = 7923002121112.

The previous prime is 7923002121109. The next prime is 7923002121191. The reversal of 7923002121113 is 3111212003297.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6995242101904 + 927760019209 = 2644852^2 + 963203^2 .

It is an emirp because it is prime and its reverse (3111212003297) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7923002121113 - 22 = 7923002121109 is a prime.

It is a super-2 number, since 2×79230021211132 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 7923002121113.

It is not a weakly prime, because it can be changed into another prime (7923002121613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3961501060556 + 3961501060557.

It is an arithmetic number, because the mean of its divisors is an integer number (3961501060557).

Almost surely, 27923002121113 is an apocalyptic number.

It is an amenable number.

7923002121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

7923002121113 is an equidigital number, since it uses as much as digits as its factorization.

7923002121113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536, while the sum is 32.

The spelling of 7923002121113 in words is "seven trillion, nine hundred twenty-three billion, two million, one hundred twenty-one thousand, one hundred thirteen".