Base | Representation |
---|---|
bin | 100100111100100110… |
… | …1100110110000111001 |
3 | 21120210112220002101121 |
4 | 1021321031212300321 |
5 | 2244443303133423 |
6 | 100241044145241 |
7 | 5506123360156 |
oct | 1117115466071 |
9 | 246715802347 |
10 | 79343021113 |
11 | 30716081124 |
12 | 13463998221 |
13 | 7635ca9405 |
14 | 3ba97dd22d |
15 | 20e599845d |
hex | 1279366c39 |
79343021113 has 2 divisors, whose sum is σ = 79343021114. Its totient is φ = 79343021112.
The previous prime is 79343021089. The next prime is 79343021119. The reversal of 79343021113 is 31112034397.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75805507584 + 3537513529 = 275328^2 + 59477^2 .
It is an emirp because it is prime and its reverse (31112034397) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 79343021113 - 229 = 78806150201 is a prime.
It is not a weakly prime, because it can be changed into another prime (79343021119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39671510556 + 39671510557.
It is an arithmetic number, because the mean of its divisors is an integer number (39671510557).
Almost surely, 279343021113 is an apocalyptic number.
It is an amenable number.
79343021113 is a deficient number, since it is larger than the sum of its proper divisors (1).
79343021113 is an equidigital number, since it uses as much as digits as its factorization.
79343021113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13608, while the sum is 34.
The spelling of 79343021113 in words is "seventy-nine billion, three hundred forty-three million, twenty-one thousand, one hundred thirteen".
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