Base | Representation |
---|---|
bin | 1011010010010111000010010… |
… | …0010011100001010011000111 |
3 | 10212011011220101010022122001101 |
4 | 2310211300210103201103013 |
5 | 1313100334423140424112 |
6 | 11453114132333440531 |
7 | 326203113311435131 |
oct | 26445604423412307 |
9 | 3764156333278041 |
10 | 794243141342407 |
11 | 210085696459129 |
12 | 750b5785040147 |
13 | 28123a6487c013 |
14 | 1001b804a2c051 |
15 | 61c5147de3757 |
hex | 2d25c244e14c7 |
794243141342407 has 2 divisors, whose sum is σ = 794243141342408. Its totient is φ = 794243141342406.
The previous prime is 794243141342393. The next prime is 794243141342507. The reversal of 794243141342407 is 704243141342497.
It is a weak prime.
It is an emirp because it is prime and its reverse (704243141342497) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-794243141342407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (794243141342507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 397121570671203 + 397121570671204.
It is an arithmetic number, because the mean of its divisors is an integer number (397121570671204).
Almost surely, 2794243141342407 is an apocalyptic number.
794243141342407 is a deficient number, since it is larger than the sum of its proper divisors (1).
794243141342407 is an equidigital number, since it uses as much as digits as its factorization.
794243141342407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16257024, while the sum is 55.
The spelling of 794243141342407 in words is "seven hundred ninety-four trillion, two hundred forty-three billion, one hundred forty-one million, three hundred forty-two thousand, four hundred seven".
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