Base | Representation |
---|---|
bin | 111001111100011110101… |
… | …1011100011101001010101 |
3 | 1001012100012212212102202212 |
4 | 1303320331123203221111 |
5 | 2020440031400011403 |
6 | 24534322023443205 |
7 | 1451241603042266 |
oct | 163707533435125 |
9 | 31170185772685 |
10 | 7963900000853 |
11 | 25a051aa285a5 |
12 | a87559bb6505 |
13 | 459cb9820014 |
14 | 1d765203496d |
15 | dc25ca4e4d8 |
hex | 73e3d6e3a55 |
7963900000853 has 2 divisors, whose sum is σ = 7963900000854. Its totient is φ = 7963900000852.
The previous prime is 7963900000789. The next prime is 7963900000907. The reversal of 7963900000853 is 3580000093697.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6429257217604 + 1534642783249 = 2535598^2 + 1238807^2 .
It is a cyclic number.
It is not a de Polignac number, because 7963900000853 - 26 = 7963900000789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7963900000253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3981950000426 + 3981950000427.
It is an arithmetic number, because the mean of its divisors is an integer number (3981950000427).
Almost surely, 27963900000853 is an apocalyptic number.
It is an amenable number.
7963900000853 is a deficient number, since it is larger than the sum of its proper divisors (1).
7963900000853 is an equidigital number, since it uses as much as digits as its factorization.
7963900000853 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 50.
The spelling of 7963900000853 in words is "seven trillion, nine hundred sixty-three billion, nine hundred million, eight hundred fifty-three", and thus it is an aban number.
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