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80100611051023 is a prime number
BaseRepresentation
bin10010001101100111100000…
…011101111100111000001111
3101111121112200022021222022001
4102031213200131330320033
540444332022412113043
6442205413540333131
722605035546002603
oct2215474035747017
9344545608258261
1080100611051023
11235825297a0992
128b980506a41a7
1335905bc1395c4
1415acc66c37503
1593d90262574d
hex48d9e077ce0f

80100611051023 has 2 divisors, whose sum is σ = 80100611051024. Its totient is φ = 80100611051022.

The previous prime is 80100611050939. The next prime is 80100611051057. The reversal of 80100611051023 is 32015011600108.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-80100611051023 is a prime.

It is a super-2 number, since 2×801006110510232 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 80100611050982 and 80100611051000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (80100611051423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40050305525511 + 40050305525512.

It is an arithmetic number, because the mean of its divisors is an integer number (40050305525512).

Almost surely, 280100611051023 is an apocalyptic number.

80100611051023 is a deficient number, since it is larger than the sum of its proper divisors (1).

80100611051023 is an equidigital number, since it uses as much as digits as its factorization.

80100611051023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 28.

The spelling of 80100611051023 in words is "eighty trillion, one hundred billion, six hundred eleven million, fifty-one thousand, twenty-three".