Base | Representation |
---|---|
bin | 100101010011010110… |
… | …0000011111001100101 |
3 | 21122202201112101112101 |
4 | 1022212230003321211 |
5 | 2303024112320433 |
6 | 100444501052101 |
7 | 5534046406501 |
oct | 1124654037145 |
9 | 248681471471 |
10 | 80105979493 |
11 | 30a77812041 |
12 | 136373b7031 |
13 | 7728090187 |
14 | 3c3cc85301 |
15 | 213c95507d |
hex | 12a6b03e65 |
80105979493 has 2 divisors, whose sum is σ = 80105979494. Its totient is φ = 80105979492.
The previous prime is 80105979469. The next prime is 80105979563. The reversal of 80105979493 is 39497950108.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55734710724 + 24371268769 = 236082^2 + 156113^2 .
It is a cyclic number.
It is not a de Polignac number, because 80105979493 - 213 = 80105971301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80105979193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40052989746 + 40052989747.
It is an arithmetic number, because the mean of its divisors is an integer number (40052989747).
Almost surely, 280105979493 is an apocalyptic number.
It is an amenable number.
80105979493 is a deficient number, since it is larger than the sum of its proper divisors (1).
80105979493 is an equidigital number, since it uses as much as digits as its factorization.
80105979493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 55.
The spelling of 80105979493 in words is "eighty billion, one hundred five million, nine hundred seventy-nine thousand, four hundred ninety-three".
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