Base | Representation |
---|---|
bin | 101111110000011… |
… | …110001000100101 |
3 | 2001211122222110122 |
4 | 233300132020211 |
5 | 3120104013433 |
6 | 211301131325 |
7 | 25566250352 |
oct | 5760361045 |
9 | 2054588418 |
10 | 801235493 |
11 | 3813050a3 |
12 | 1a43b9b45 |
13 | c9cc6356 |
14 | 785ab629 |
15 | 4a51d198 |
hex | 2fc1e225 |
801235493 has 2 divisors, whose sum is σ = 801235494. Its totient is φ = 801235492.
The previous prime is 801235441. The next prime is 801235531. The reversal of 801235493 is 394532108.
801235493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 420127009 + 381108484 = 20497^2 + 19522^2 .
It is a cyclic number.
It is not a de Polignac number, because 801235493 - 212 = 801231397 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (801235433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 400617746 + 400617747.
It is an arithmetic number, because the mean of its divisors is an integer number (400617747).
Almost surely, 2801235493 is an apocalyptic number.
It is an amenable number.
801235493 is a deficient number, since it is larger than the sum of its proper divisors (1).
801235493 is an equidigital number, since it uses as much as digits as its factorization.
801235493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The square root of 801235493 is about 28306.1034584416. The cubic root of 801235493 is about 928.7954084650.
The spelling of 801235493 in words is "eight hundred one million, two hundred thirty-five thousand, four hundred ninety-three".
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