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8012914987733 is a prime number
BaseRepresentation
bin111010010011010011011…
…1100111001001011010101
31001101000201211012202102022
41310212212330321023111
52022240422214101413
625013025441022525
71454625334413545
oct164464674711325
931330654182368
108012914987733
11260a292683717
12a94b59024a45
134617cb49c236
141d9b819d9325
15dd67abc3608
hex749a6f392d5

8012914987733 has 2 divisors, whose sum is σ = 8012914987734. Its totient is φ = 8012914987732.

The previous prime is 8012914987631. The next prime is 8012914987823. The reversal of 8012914987733 is 3377894192108.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7459770262564 + 553144725169 = 2731258^2 + 743737^2 .

It is a cyclic number.

It is not a de Polignac number, because 8012914987733 - 28 = 8012914987477 is a prime.

It is a super-4 number, since 4×80129149877334 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8012914986733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4006457493866 + 4006457493867.

It is an arithmetic number, because the mean of its divisors is an integer number (4006457493867).

Almost surely, 28012914987733 is an apocalyptic number.

It is an amenable number.

8012914987733 is a deficient number, since it is larger than the sum of its proper divisors (1).

8012914987733 is an equidigital number, since it uses as much as digits as its factorization.

8012914987733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18289152, while the sum is 62.

The spelling of 8012914987733 in words is "eight trillion, twelve billion, nine hundred fourteen million, nine hundred eighty-seven thousand, seven hundred thirty-three".