Base | Representation |
---|---|
bin | 111010010011100000100… |
… | …1011100011010110000011 |
3 | 1001101001212111020122000102 |
4 | 1310213001023203112003 |
5 | 2022242322342204313 |
6 | 25013141240513015 |
7 | 1454642256653303 |
oct | 164470113432603 |
9 | 31331774218012 |
10 | 8013355038083 |
11 | 260a499013a9a |
12 | a9506047b76b |
13 | 46186b6c4265 |
14 | 1d9bc4227603 |
15 | dd6a4648a58 |
hex | 749c12e3583 |
8013355038083 has 2 divisors, whose sum is σ = 8013355038084. Its totient is φ = 8013355038082.
The previous prime is 8013355038071. The next prime is 8013355038089. The reversal of 8013355038083 is 3808305533108.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 8013355038083 - 210 = 8013355037059 is a prime.
It is not a weakly prime, because it can be changed into another prime (8013355038089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4006677519041 + 4006677519042.
It is an arithmetic number, because the mean of its divisors is an integer number (4006677519042).
Almost surely, 28013355038083 is an apocalyptic number.
8013355038083 is a deficient number, since it is larger than the sum of its proper divisors (1).
8013355038083 is an equidigital number, since it uses as much as digits as its factorization.
8013355038083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 47.
The spelling of 8013355038083 in words is "eight trillion, thirteen billion, three hundred fifty-five million, thirty-eight thousand, eighty-three".
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