Base | Representation |
---|---|
bin | 111010010011100100010… |
… | …1100011111011101111110 |
3 | 1001101002012021110220221012 |
4 | 1310213020230133131332 |
5 | 2022243102131112340 |
6 | 25013201543035222 |
7 | 1454645350410110 |
oct | 164471054373576 |
9 | 31332167426835 |
10 | 8013481113470 |
11 | 260a5531a5328 |
12 | a9509673bb12 |
13 | 46188b867591 |
14 | 1d9bd6c853b0 |
15 | dd6b074e565 |
hex | 749c8b1f77e |
8013481113470 has 16 divisors (see below), whose sum is σ = 16484875433568. Its totient is φ = 2747479238880.
The previous prime is 8013481113437. The next prime is 8013481113493. The reversal of 8013481113470 is 743111843108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57239150741 + ... + 57239150880.
It is an arithmetic number, because the mean of its divisors is an integer number (1030304714598).
Almost surely, 28013481113470 is an apocalyptic number.
8013481113470 is an abundant number, since it is smaller than the sum of its proper divisors (8471394320098).
8013481113470 is a wasteful number, since it uses less digits than its factorization.
8013481113470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114478301635.
The product of its (nonzero) digits is 64512, while the sum is 41.
Adding to 8013481113470 its reverse (743111843108), we get a palindrome (8756592956578).
The spelling of 8013481113470 in words is "eight trillion, thirteen billion, four hundred eighty-one million, one hundred thirteen thousand, four hundred seventy".
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