Base | Representation |
---|---|
bin | 100101010100100001… |
… | …0111001001110100001 |
3 | 21122212110221020020212 |
4 | 1022221002321032201 |
5 | 2303114223111041 |
6 | 100452432343505 |
7 | 5535036450524 |
oct | 1125102711641 |
9 | 248773836225 |
10 | 80145519521 |
11 | 30a98069051 |
12 | 136486a4b95 |
13 | 7733325542 |
14 | 3c44218bbb |
15 | 21411658eb |
hex | 12a90b93a1 |
80145519521 has 2 divisors, whose sum is σ = 80145519522. Its totient is φ = 80145519520.
The previous prime is 80145519511. The next prime is 80145519523. The reversal of 80145519521 is 12591554108.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74507161600 + 5638357921 = 272960^2 + 75089^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-80145519521 is a prime.
It is a Sophie Germain prime.
Together with 80145519523, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (80145519523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40072759760 + 40072759761.
It is an arithmetic number, because the mean of its divisors is an integer number (40072759761).
Almost surely, 280145519521 is an apocalyptic number.
It is an amenable number.
80145519521 is a deficient number, since it is larger than the sum of its proper divisors (1).
80145519521 is an equidigital number, since it uses as much as digits as its factorization.
80145519521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 41.
The spelling of 80145519521 in words is "eighty billion, one hundred forty-five million, five hundred nineteen thousand, five hundred twenty-one".
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