Base | Representation |
---|---|
bin | 111010010100110011101… |
… | …1110000111001011001101 |
3 | 1001101100001220220101022012 |
4 | 1310221213132013023031 |
5 | 2022314031044440133 |
6 | 25014322141431005 |
7 | 1455101354404505 |
oct | 164514736071315 |
9 | 31340056811265 |
10 | 8016144921293 |
11 | 261069a9115a3 |
12 | a956ba86b465 |
13 | 461bc46bb722 |
14 | 1d9daa976a05 |
15 | dd7b9535b48 |
hex | 74a677872cd |
8016144921293 has 2 divisors, whose sum is σ = 8016144921294. Its totient is φ = 8016144921292.
The previous prime is 8016144921277. The next prime is 8016144921347. The reversal of 8016144921293 is 3921294416108.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5464831939204 + 2551312982089 = 2337698^2 + 1597283^2 .
It is a cyclic number.
It is not a de Polignac number, because 8016144921293 - 24 = 8016144921277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8016144921493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4008072460646 + 4008072460647.
It is an arithmetic number, because the mean of its divisors is an integer number (4008072460647).
Almost surely, 28016144921293 is an apocalyptic number.
It is an amenable number.
8016144921293 is a deficient number, since it is larger than the sum of its proper divisors (1).
8016144921293 is an equidigital number, since it uses as much as digits as its factorization.
8016144921293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 50.
The spelling of 8016144921293 in words is "eight trillion, sixteen billion, one hundred forty-four million, nine hundred twenty-one thousand, two hundred ninety-three".
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