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80252913407 is a prime number
BaseRepresentation
bin100101010111101110…
…0100100011011111111
321200010222000101222012
41022233130210123333
52303324221212112
6100511230241435
75540512336322
oct1125734443377
9250128011865
1080252913407
113104274a727
121367865627b
13774c657614
143c545b27b9
15214a7cb022
hex12af7246ff

80252913407 has 2 divisors, whose sum is σ = 80252913408. Its totient is φ = 80252913406.

The previous prime is 80252913373. The next prime is 80252913427. The reversal of 80252913407 is 70431925208.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 80252913407 - 218 = 80252651263 is a prime.

It is a super-2 number, since 2×802529134072 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (80252913427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40126456703 + 40126456704.

It is an arithmetic number, because the mean of its divisors is an integer number (40126456704).

Almost surely, 280252913407 is an apocalyptic number.

80252913407 is a deficient number, since it is larger than the sum of its proper divisors (1).

80252913407 is an equidigital number, since it uses as much as digits as its factorization.

80252913407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 41.

The spelling of 80252913407 in words is "eighty billion, two hundred fifty-two million, nine hundred thirteen thousand, four hundred seven".