Base | Representation |
---|---|
bin | 100101010111101110… |
… | …0100100011011111111 |
3 | 21200010222000101222012 |
4 | 1022233130210123333 |
5 | 2303324221212112 |
6 | 100511230241435 |
7 | 5540512336322 |
oct | 1125734443377 |
9 | 250128011865 |
10 | 80252913407 |
11 | 3104274a727 |
12 | 1367865627b |
13 | 774c657614 |
14 | 3c545b27b9 |
15 | 214a7cb022 |
hex | 12af7246ff |
80252913407 has 2 divisors, whose sum is σ = 80252913408. Its totient is φ = 80252913406.
The previous prime is 80252913373. The next prime is 80252913427. The reversal of 80252913407 is 70431925208.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 80252913407 - 218 = 80252651263 is a prime.
It is a super-2 number, since 2×802529134072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80252913427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40126456703 + 40126456704.
It is an arithmetic number, because the mean of its divisors is an integer number (40126456704).
Almost surely, 280252913407 is an apocalyptic number.
80252913407 is a deficient number, since it is larger than the sum of its proper divisors (1).
80252913407 is an equidigital number, since it uses as much as digits as its factorization.
80252913407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 80252913407 in words is "eighty billion, two hundred fifty-two million, nine hundred thirteen thousand, four hundred seven".
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