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8025664343 is a prime number
BaseRepresentation
bin1110111100101110…
…11110101101010111
3202201022200222202112
413132113132231113
5112414032224333
63404213501235
7402612010214
oct73627365527
922638628675
108025664343
113449307454
12167b94181b
139ab95a818
14561c68b0b
1531e8b9948
hex1de5deb57

8025664343 has 2 divisors, whose sum is σ = 8025664344. Its totient is φ = 8025664342.

The previous prime is 8025664261. The next prime is 8025664357. The reversal of 8025664343 is 3434665208.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-8025664343 is a prime.

It is a super-2 number, since 2×80256643432 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 8025664343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8025664373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4012832171 + 4012832172.

It is an arithmetic number, because the mean of its divisors is an integer number (4012832172).

Almost surely, 28025664343 is an apocalyptic number.

8025664343 is a deficient number, since it is larger than the sum of its proper divisors (1).

8025664343 is an equidigital number, since it uses as much as digits as its factorization.

8025664343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 41.

The square root of 8025664343 is about 89586.0722601454. The cubic root of 8025664343 is about 2002.1364123086.

The spelling of 8025664343 in words is "eight billion, twenty-five million, six hundred sixty-four thousand, three hundred forty-three".