Search a number
-
+
804010057093 is a prime number
BaseRepresentation
bin10111011001100101011…
…10111101110110000101
32211212021211202202011201
423230302232331312011
5101133103033311333
61413205045502501
7112042055503405
oct13546256756605
92755254682151
10804010057093
1128aa84797a71
1210b9a5411a31
135aa829ac919
142acb2b76805
1515daa3a217d
hexbb32bbdd85

804010057093 has 2 divisors, whose sum is σ = 804010057094. Its totient is φ = 804010057092.

The previous prime is 804010057061. The next prime is 804010057117. The reversal of 804010057093 is 390750010408.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 597168836289 + 206841220804 = 772767^2 + 454798^2 .

It is a cyclic number.

It is not a de Polignac number, because 804010057093 - 25 = 804010057061 is a prime.

It is a super-2 number, since 2×8040100570932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (804010057013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 402005028546 + 402005028547.

It is an arithmetic number, because the mean of its divisors is an integer number (402005028547).

Almost surely, 2804010057093 is an apocalyptic number.

It is an amenable number.

804010057093 is a deficient number, since it is larger than the sum of its proper divisors (1).

804010057093 is an equidigital number, since it uses as much as digits as its factorization.

804010057093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 37.

The spelling of 804010057093 in words is "eight hundred four billion, ten million, fifty-seven thousand, ninety-three".