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80402410493 is a prime number
BaseRepresentation
bin100101011100001011…
…0110110101111111101
321200112101022122102022
41022320112312233331
52304131004113433
6100534130405525
75544306133016
oct1127026665775
9250471278368
1080402410493
113110a079039
12136ba7308a5
13777460b632
143c6a3aa00d
1521589ab698
hex12b85b6bfd

80402410493 has 2 divisors, whose sum is σ = 80402410494. Its totient is φ = 80402410492.

The previous prime is 80402410463. The next prime is 80402410549. The reversal of 80402410493 is 39401420408.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61803451609 + 18598958884 = 248603^2 + 136378^2 .

It is a cyclic number.

It is not a de Polignac number, because 80402410493 - 28 = 80402410237 is a prime.

It is a super-2 number, since 2×804024104932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (80402410423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40201205246 + 40201205247.

It is an arithmetic number, because the mean of its divisors is an integer number (40201205247).

Almost surely, 280402410493 is an apocalyptic number.

It is an amenable number.

80402410493 is a deficient number, since it is larger than the sum of its proper divisors (1).

80402410493 is an equidigital number, since it uses as much as digits as its factorization.

80402410493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 80402410493 in words is "eighty billion, four hundred two million, four hundred ten thousand, four hundred ninety-three".