Base | Representation |
---|---|
bin | 100101011100001111… |
… | …0001110001000110101 |
3 | 21200112111221201222201 |
4 | 1022320132032020311 |
5 | 2304132002410201 |
6 | 100534240024501 |
7 | 5544331424134 |
oct | 1127036161065 |
9 | 250474851881 |
10 | 80404341301 |
11 | 31110177749 |
12 | 136bb302131 |
13 | 7774b3641b |
14 | 3c6a74d91b |
15 | 2158c3d801 |
hex | 12b878e235 |
80404341301 has 2 divisors, whose sum is σ = 80404341302. Its totient is φ = 80404341300.
The previous prime is 80404341217. The next prime is 80404341307. The reversal of 80404341301 is 10314340408.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46084926276 + 34319415025 = 214674^2 + 185255^2 .
It is a cyclic number.
It is not a de Polignac number, because 80404341301 - 29 = 80404340789 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 80404341301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80404341307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40202170650 + 40202170651.
It is an arithmetic number, because the mean of its divisors is an integer number (40202170651).
Almost surely, 280404341301 is an apocalyptic number.
It is an amenable number.
80404341301 is a deficient number, since it is larger than the sum of its proper divisors (1).
80404341301 is an equidigital number, since it uses as much as digits as its factorization.
80404341301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 80404341301 its reverse (10314340408), we get a palindrome (90718681709).
The spelling of 80404341301 in words is "eighty billion, four hundred four million, three hundred forty-one thousand, three hundred one".
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