Base | Representation |
---|---|
bin | 10010010010000100101001… |
… | …001100010011110101110111 |
3 | 101112200210221022121011221211 |
4 | 102102010221030103311313 |
5 | 41014341033100410041 |
6 | 443002210103422251 |
7 | 22636124545533613 |
oct | 2222045114236567 |
9 | 345623838534854 |
10 | 80406773841271 |
11 | 236903596a6769 |
12 | 9027455a54987 |
13 | 35b3431990757 |
14 | 15bd9cc642343 |
15 | 946870d76481 |
hex | 492129313d77 |
80406773841271 has 2 divisors, whose sum is σ = 80406773841272. Its totient is φ = 80406773841270.
The previous prime is 80406773841257. The next prime is 80406773841283. The reversal of 80406773841271 is 17214837760408.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-80406773841271 is a prime.
It is a super-2 number, since 2×804067738412712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80406773842271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40203386920635 + 40203386920636.
It is an arithmetic number, because the mean of its divisors is an integer number (40203386920636).
Almost surely, 280406773841271 is an apocalyptic number.
80406773841271 is a deficient number, since it is larger than the sum of its proper divisors (1).
80406773841271 is an equidigital number, since it uses as much as digits as its factorization.
80406773841271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12644352, while the sum is 58.
The spelling of 80406773841271 in words is "eighty trillion, four hundred six billion, seven hundred seventy-three million, eight hundred forty-one thousand, two hundred seventy-one".
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