Base | Representation |
---|---|
bin | 10010010010001100101011… |
… | …001001010100000110011111 |
3 | 101112201122012020201220200111 |
4 | 102102030223021110012133 |
5 | 41020011213003414202 |
6 | 443010153450110451 |
7 | 22636551330362413 |
oct | 2222145311240637 |
9 | 345648166656614 |
10 | 80415396544927 |
11 | 23693a83a19634 |
12 | 902906171b427 |
13 | 35b41a721b372 |
14 | 15c01a98c2d43 |
15 | 946bc7d766d7 |
hex | 49232b25419f |
80415396544927 has 2 divisors, whose sum is σ = 80415396544928. Its totient is φ = 80415396544926.
The previous prime is 80415396544853. The next prime is 80415396544939. The reversal of 80415396544927 is 72944569351408.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 80415396544927 - 223 = 80415388156319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80415396545927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40207698272463 + 40207698272464.
It is an arithmetic number, because the mean of its divisors is an integer number (40207698272464).
It is a 1-persistent number, because it is pandigital, but 2⋅80415396544927 = 160830793089854 is not.
Almost surely, 280415396544927 is an apocalyptic number.
80415396544927 is a deficient number, since it is larger than the sum of its proper divisors (1).
80415396544927 is an equidigital number, since it uses as much as digits as its factorization.
80415396544927 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 261273600, while the sum is 67.
The spelling of 80415396544927 in words is "eighty trillion, four hundred fifteen billion, three hundred ninety-six million, five hundred forty-four thousand, nine hundred twenty-seven".
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