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80423171 is a prime number
BaseRepresentation
bin1001100101100…
…10100100000011
312121022220211222
410302302210003
5131042020141
611551425255
71664404613
oct462624403
9177286758
1080423171
1141440134
1222b2522b
131387ab9a
14a976a43
1570d914b
hex4cb2903

80423171 has 2 divisors, whose sum is σ = 80423172. Its totient is φ = 80423170.

The previous prime is 80423137. The next prime is 80423173. The reversal of 80423171 is 17132408.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-80423171 is a prime.

Together with 80423173, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 80423171.

It is not a weakly prime, because it can be changed into another prime (80423173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40211585 + 40211586.

It is an arithmetic number, because the mean of its divisors is an integer number (40211586).

Almost surely, 280423171 is an apocalyptic number.

80423171 is a deficient number, since it is larger than the sum of its proper divisors (1).

80423171 is an equidigital number, since it uses as much as digits as its factorization.

80423171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 26.

The square root of 80423171 is about 8967.8966876297. The cubic root of 80423171 is about 431.6453475721.

Adding to 80423171 its reverse (17132408), we get a palindrome (97555579).

The spelling of 80423171 in words is "eighty million, four hundred twenty-three thousand, one hundred seventy-one".