Base | Representation |
---|---|
bin | 111010100001111101111… |
… | …0010111010000100110001 |
3 | 1001111001000021211220021021 |
4 | 1311003323302322010301 |
5 | 2023244414210020101 |
6 | 25035314154455441 |
7 | 1460121545012524 |
oct | 165037362720461 |
9 | 31431007756237 |
10 | 8044403204401 |
11 | 2621680989983 |
12 | a9b086434581 |
13 | 464778c8c0c5 |
14 | 1db4cb95abbb |
15 | de3c02ba5a1 |
hex | 750fbcba131 |
8044403204401 has 2 divisors, whose sum is σ = 8044403204402. Its totient is φ = 8044403204400.
The previous prime is 8044403204359. The next prime is 8044403204429. The reversal of 8044403204401 is 1044023044408.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6757088313600 + 1287314890801 = 2599440^2 + 1134599^2 .
It is a cyclic number.
It is not a de Polignac number, because 8044403204401 - 213 = 8044403196209 is a prime.
It is not a weakly prime, because it can be changed into another prime (8044403234401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4022201602200 + 4022201602201.
It is an arithmetic number, because the mean of its divisors is an integer number (4022201602201).
Almost surely, 28044403204401 is an apocalyptic number.
It is an amenable number.
8044403204401 is a deficient number, since it is larger than the sum of its proper divisors (1).
8044403204401 is an equidigital number, since it uses as much as digits as its factorization.
8044403204401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 49152, while the sum is 34.
Adding to 8044403204401 its reverse (1044023044408), we get a palindrome (9088426248809).
The spelling of 8044403204401 in words is "eight trillion, forty-four billion, four hundred three million, two hundred four thousand, four hundred one".
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