Base | Representation |
---|---|
bin | 100101011111010111… |
… | …0101111001000100101 |
3 | 21200210211111220222011 |
4 | 1022332232233020211 |
5 | 2304340342142203 |
6 | 100552510234221 |
7 | 5550045022351 |
oct | 1127656571045 |
9 | 250724456864 |
10 | 80509334053 |
11 | 31164469315 |
12 | 1372a4b5971 |
13 | 7790807605 |
14 | 3c7a680461 |
15 | 216307c76d |
hex | 12bebaf225 |
80509334053 has 2 divisors, whose sum is σ = 80509334054. Its totient is φ = 80509334052.
The previous prime is 80509334033. The next prime is 80509334099. The reversal of 80509334053 is 35043390508.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54927890689 + 25581443364 = 234367^2 + 159942^2 .
It is a cyclic number.
It is not a de Polignac number, because 80509334053 - 217 = 80509202981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 80509333997 and 80509334015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80509334023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40254667026 + 40254667027.
It is an arithmetic number, because the mean of its divisors is an integer number (40254667027).
Almost surely, 280509334053 is an apocalyptic number.
It is an amenable number.
80509334053 is a deficient number, since it is larger than the sum of its proper divisors (1).
80509334053 is an equidigital number, since it uses as much as digits as its factorization.
80509334053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 194400, while the sum is 40.
The spelling of 80509334053 in words is "eighty billion, five hundred nine million, three hundred thirty-four thousand, fifty-three".
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