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806414578217 is a prime number
BaseRepresentation
bin10111011110000100000…
…11011111001000101001
32212002111102022002001122
423233002003133020221
5101203014113000332
61414243423025025
7112155463550153
oct13570203371051
92762442262048
10806414578217
11290aa9008306
1211035673b175
135b076bbc3a1
142b060251ad3
1515e9b51cc12
hexbbc20df229

806414578217 has 2 divisors, whose sum is σ = 806414578218. Its totient is φ = 806414578216.

The previous prime is 806414578213. The next prime is 806414578273. The reversal of 806414578217 is 712875414608.

806414578217 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 591182605456 + 215231972761 = 768884^2 + 463931^2 .

It is a cyclic number.

It is not a de Polignac number, because 806414578217 - 22 = 806414578213 is a prime.

It is not a weakly prime, because it can be changed into another prime (806414578213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 403207289108 + 403207289109.

It is an arithmetic number, because the mean of its divisors is an integer number (403207289109).

Almost surely, 2806414578217 is an apocalyptic number.

It is an amenable number.

806414578217 is a deficient number, since it is larger than the sum of its proper divisors (1).

806414578217 is an equidigital number, since it uses as much as digits as its factorization.

806414578217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3010560, while the sum is 53.

The spelling of 806414578217 in words is "eight hundred six billion, four hundred fourteen million, five hundred seventy-eight thousand, two hundred seventeen".