Base | Representation |
---|---|
bin | 10010010101100111110100… |
… | …101101100100100111001111 |
3 | 101120120010120101221101020011 |
4 | 102111213310231210213033 |
5 | 41032340121331113033 |
6 | 443310231215134051 |
7 | 22662551456132056 |
oct | 2225476455444717 |
9 | 346503511841204 |
10 | 80650706504143 |
11 | 23774855297806 |
12 | 9066792514327 |
13 | 3600437a38119 |
14 | 15cb72d31739d |
15 | 94cd9b1a5ccd |
hex | 4959f4b649cf |
80650706504143 has 2 divisors, whose sum is σ = 80650706504144. Its totient is φ = 80650706504142.
The previous prime is 80650706504009. The next prime is 80650706504177. The reversal of 80650706504143 is 34140560705608.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 80650706504143 - 213 = 80650706495951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80650706534143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40325353252071 + 40325353252072.
It is an arithmetic number, because the mean of its divisors is an integer number (40325353252072).
Almost surely, 280650706504143 is an apocalyptic number.
80650706504143 is a deficient number, since it is larger than the sum of its proper divisors (1).
80650706504143 is an equidigital number, since it uses as much as digits as its factorization.
80650706504143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 49.
The spelling of 80650706504143 in words is "eighty trillion, six hundred fifty billion, seven hundred six million, five hundred four thousand, one hundred forty-three".
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