Search a number
-
+
8068550659667 is a prime number
BaseRepresentation
bin111010101101001101100…
…0110001000111001010011
31001120100100011112201120022
41311122123012020321103
52024143342432102132
625054350242334055
71461635131003661
oct165323306107123
931510304481508
108068550659667
112630942556483
12aa38a535a32b
13466b269a5c84
141dc73c9bbc31
15ded351d6e12
hex7569b188e53

8068550659667 has 2 divisors, whose sum is σ = 8068550659668. Its totient is φ = 8068550659666.

The previous prime is 8068550659613. The next prime is 8068550659669. The reversal of 8068550659667 is 7669560558608.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-8068550659667 is a prime.

It is a super-2 number, since 2×80685506596672 (a number of 27 digits) contains 22 as substring.

Together with 8068550659669, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 8068550659667.

It is not a weakly prime, because it can be changed into another prime (8068550659669) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4034275329833 + 4034275329834.

It is an arithmetic number, because the mean of its divisors is an integer number (4034275329834).

Almost surely, 28068550659667 is an apocalyptic number.

8068550659667 is a deficient number, since it is larger than the sum of its proper divisors (1).

8068550659667 is an equidigital number, since it uses as much as digits as its factorization.

8068550659667 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184000, while the sum is 71.

The spelling of 8068550659667 in words is "eight trillion, sixty-eight billion, five hundred fifty million, six hundred fifty-nine thousand, six hundred sixty-seven".